Question on: JAMB Mathematics - 1992
p = (\begin{vmatrix} x & 3 & 0 \ 2 & y & 3\ 4 & 2 & 4 \end{vmatrix})
Q = (\begin{vmatrix} x & 2 & z \ 3 & y & 2\ 0 & 3 & z \end{vmatrix})
PQ is equivalent to
A
PPT
B
pp-1
C
qp
D
pp
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Correct Option: A
p = (\begin{vmatrix} 0 & 3 & 0 \ 2 & 1 & 3\ 4 & 2 & 2 \end{vmatrix})
Q = (\begin{vmatrix} 0 & 2 & 4 \ 3 & 1 & 2\ 0 & 3 & 2 \end{vmatrix}) = pT
pq = ppT
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