p begin vmatrix x amp 3 amp 0 2 amp y amp 3 4 a... - JAMB Mathematics 1992 Question
p = \(\begin{vmatrix} x & 3 & 0 \ 2 & y & 3\ 4 & 2 & 4 \end{vmatrix}\)
Q = \(\begin{vmatrix} x & 2 & z \ 3 & y & 2\ 0 & 3 & z \end{vmatrix}\)
PQ is equivalent to
Q = \(\begin{vmatrix} x & 2 & z \ 3 & y & 2\ 0 & 3 & z \end{vmatrix}\)
PQ is equivalent to
A
PPT
B
pp-1
C
qp
D
pp
correct option: a
p = \(\begin{vmatrix} 0 & 3 & 0 \ 2 & 1 & 3\ 4 & 2 & 2 \end{vmatrix}\)
Q = \(\begin{vmatrix} 0 & 2 & 4 \ 3 & 1 & 2\ 0 & 3 & 2 \end{vmatrix}\) = pT
pq = ppT
Q = \(\begin{vmatrix} 0 & 2 & 4 \ 3 & 1 & 2\ 0 & 3 & 2 \end{vmatrix}\) = pT
pq = ppT
Please share this, thanks:
Add your answer
No responses